July 10th, 2001

Round Graphite
Algebra problem. Help?

I don’t know how to do this so, i’m going to type in the directions.

Mineralogists use the Vickers scale to measure the hardness of minerals. The hardness “H” of a mineral can be determined by hitting the mineral with a pyramid shaped diamond and measure the depth “d” of the indentation. The harder the mineral, the smaller the depth of the indentation. A model that relates mineral hardness with the indentation depth (in millineters) is Hd2=1.89. (The 2 is squared, but I don’t know how to do it.)

Use a calculator to find the depth of the indentation for the mineral with the given value of “H”. Round to the nearest hundredth of a millimeter.

Graphite: H = 12.

How do I solve this? Can you please show it step by step if you do know how? Thanks.

Hd^2 = 1.89
d^2 = 1.89/H
d = sqrt(1.89/H)

d = sqrt(1.89/12)
d = sqrt(0.1575)
d = 0.3969

Best of luck!

Yamaha r6 08 graphite akrapovic 001


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